313_Chemistry_Eng_Lesson27.pdf). Content covers sections 27.1–27.2.Aldehydes (RCHO), ketones (R₂C=O) and carboxylic acids (RCOOH) contain the carbon–oxygen double bond. They flavour foods, serve as solvents and reagents, and are central to organic synthesis. This lesson covers nomenclature, preparation, polar C=O chemistry, nucleophilic addition, distinguishing tests, α-hydrogen reactions (aldol, haloform, Cannizzaro), and the preparation, acidity and reactions of carboxylic acids.
Carbonyl C and O are sp² hybridised; molecule is planar about C=O. Oxygen is more electronegative → Cδ⁺=Oδ⁻. Carbon is electrophilic (Nu attack); oxygen is nucleophilic/basic (E⁺/H⁺). Dipole interactions raise b.p. vs hydrocarbons; H-bonding with water gives lower members good solubility.
Aldehydes more reactive than ketones: (i) only one +I alkyl group → more positive carbonyl C; (ii) less steric crowding.
Naming: alkanals (-al), alkanones (-one); common names acetone, acetophenone, benzaldehyde, formaldehyde. Carbonyl carbon gets lowest number; for ketones the -one suffix is numbered (propan-2-one). Aromatic aldehydes often keep common names (benzaldehyde).
Preparation (overview): oxidation of 1° alcohols → aldehydes (controlled, e.g. PCC or distillation of product); 2° alcohols → ketones (K₂Cr₂O₇/H⁺ or PCC); ozonolysis of alkenes (reductive work-up); hydration of alkynes (Hg²⁺/H⁺ → ethanal from ethyne, methyl ketones from terminal alkynes); Friedel–Crafts acylation (ArH + RCOCl/AlCl₃) → aromatic ketones; Rosenmund (RCOCl + H₂/Pd-BaSO₄ → RCHO — poisoned catalyst stops at aldehyde); Stephen reduction of nitriles (SnCl₂/HCl then H₃O⁺ → RCHO); dry distillation of calcium carboxylates for ketones (higher level).
Physical properties: lower aldehydes/ketones are liquids with characteristic odours. Boiling points higher than hydrocarbons of similar mass (dipole–dipole) but lower than alcohols (no O–H H-bonding between pure carbonyl molecules). Methanal, ethanal and propanone mix well with water; solubility falls as the hydrophobic R grows.
A. Nucleophilic addition: HCN → cyanohydrins (useful C–C bond; hydrolyse to α-hydroxy acids); NaHSO₃ adducts (crystalline, reverse on acid/base); alcohols → hemiacetals then acetals (acid; protect carbonyls); water → gem-diols (hydrate, often reversible); Grignard → alcohols after acid work-up (HCHO → 1°, RCHO → 2°, R₂C=O → 3°); ammonia derivatives → imines, oximes, hydrazones, 2,4-DNP hydrazones (orange/yellow crystalline solids for m.p. identification of both aldehydes and ketones).
B. Reduction: to alcohols (NaBH₄ mild, LiAlH₄ stronger, catalytic H₂/Ni). Deoxygenation to alkanes: Wolff–Kishner (NH₂NH₂, KOH, high-boiling alcohol — base-compatible) vs Clemmensen (Zn-Hg/HCl — acid-compatible). Choose the method that does not destroy other acid- or base-sensitive groups.
C. Oxidation: aldehydes → carboxylic acids easily (even air, or KMnO₄/K₂Cr₂O₇). Tollen’s: ammoniacal AgNO₃, [Ag(NH₃)₂]⁺ → silver mirror. Fehling’s: Cu²⁺/tartrate alkaline → brick-red Cu₂O (aliphatic aldehydes; aromatic aldehydes often fail Fehling but give Tollen’s). Ketones resist these mild oxidants — classic distinction. Strong oxidants can still cleave ketones under forcing conditions (exam: mild tests are the focus).
D. α-Carbon chemistry: α-H is acidic (enolate resonance) → keto–enol tautomerism. Halogenation at α-C (acid or base); excess base + I₂ → haloform (CHI₃ yellow ppt for methyl ketones CH₃COR and compounds oxidisable to them, e.g. ethanol, ethanal). Aldol: dilute NaOH on carbonyls with α-H → β-hydroxy aldehyde/ketone; heat drives dehydration to α,β-unsaturated carbonyl (conjugated). Crossed aldol needs care (one component without α-H preferred). Cannizzaro: aldehydes without α-H (HCHO, PhCHO) + concentrated NaOH → disproportionation: one molecule oxidised to acid salt, one reduced to alcohol. Never confuse: aldol needs α-H + dilute base; Cannizzaro needs no α-H + concentrated base.
RCOOH — formic, acetic, propanoic… alkanedioic acids (oxalic, malonic), benzoic acid and substituted aromatics. Carboxyl carbon is sp²; the –COOH group is planar. In pure liquids/solids, acids form strong H-bonded dimers → high melting and boiling points relative to alcohols of similar mass. Lower members are water-soluble; long-chain fatty acids are not.
Preparation: oxidation of alkenes (hot alkaline KMnO₄, cleaves double bond), 1° alcohols and aldehydes; side-chain oxidation of Ar–CH₃ (or longer alkyl) → ArCOOH (KMnO₄/H⁺ or CrO₃ — ring must have benzylic H); Grignard + CO₂ then acid work-up (adds one carbon); hydrolysis of nitriles and cyanohydrins (acid or base, then acidify). Industrial acetic acid: methanol carbonylation and related routes (context only).
Acidity: pKₐ typically ~4–5 in water. Dissociation gives resonance-stabilised carboxylate (negative charge shared by both oxygens) — much stronger acids than alcohols (pKₐ ~16) or phenols (pKₐ ~10). −I / electron-withdrawing substituents increase acidity (ClCH₂COOH > CH₃COOH; Cl₃CCOOH is very strong); alkyl groups slightly decrease acidity. Benzoic acid is a solid aromatic acid; o-substituents can affect strength via steric and electronic effects (exam: know the inductive trend first).
Reactions: form salts with bases (NaOH, Na₂CO₃); liberate CO₂ from NaHCO₃/Na₂CO₃ (distinction from most phenols — phenols need stronger base); Fischer esterification with ROH/H⁺ (reversible; remove water to drive); form acid chlorides (SOCl₂ preferred — gaseous by-products; also PCl₅/PCl₃); amides via ammonium salt then heat dehydration; anhydrides by dehydrating agents or from RCOCl + RCOONa; reduction with LiAlH₄ → 1° alcohols (NaBH₄ usually does not reduce free RCOOH); α-halogenation (Hell–Volhard–Zelinsky) with X₂ and red phosphorus → α-halo acids for further substitution.
Derivatives: reactivity order roughly acid chloride > anhydride > ester > amide toward nucleophiles. Interconversions (e.g. RCOCl → ester or amide) are central to multi-step synthesis. Esters hydrolyse to acids (acid or base; base saponification is irreversible).
High-yield checklist: (1) polar C=O and why RCHO > R₂C=O (electronic + steric); (2) Nu addition products — cyanohydrin, acetal, oxime, 2,4-DNP; (3) Tollen’s/Fehling vs 2,4-DNP (oxidation vs carbonyl detection); (4) aldol needs α-H + dilute base, Cannizzaro needs no α-H + concentrated base; (5) iodoform for CH₃COR; (6) Wolff–Kishner (base) vs Clemmensen (acid) for C=O → CH₂; (7) acid preparation routes and pKₐ / −I trends; (8) NaHCO₃ CO₂ test vs phenols; (9) esterification and acid chlorides.
Builds on L26 (oxidation of alcohols to carbonyls and acids) and L25 (haloform chemistry). Next in the module: nitrogen compounds (L28) and biomolecules (L29). Practice writing the mechanism of nucleophilic addition and the aldol sequence — they appear repeatedly in board and competitive exams.
Most exam-important points from this chapter:
C=O polar; Nu addition at C. Aldehydes > ketones. Name -al/-one.
2,4-DNP both. Tollen’s/Fehling aldehydes only. Iodoform for methyl ketones.
Aldol needs α-H. Cannizzaro needs no α-H. Haloform for CH₃COR.
To alcohol (hydride/H₂). To alkane: Wolff–Kishner (base) or Clemmensen (acid).
Stronger than ROH/PhOH (resonance). Prep: oxidation, RMgX+CO₂, RCN. NaHCO₃ fizz. Esters & RCOCl.
Extracted from NIOS Chemistry (313) board exam papers in your PDF. Chapter L27 — Aldehydes, Ketones and Carboxylic Acids only. Use Model Answer for marking points; Explanation for concept clarity.
4 question(s) · Sources: 313/MAY/205A, 313/MAY/205B, 313/MAY/205C
PYQ1. The hydrolysis of ethylene ozonide gives — (A) formaldehyde (B) acetaldehyde (C) acetone (D) ethene EWrbrZ AmoOmoZmBS>
Model Answer
Model approach (select the best option):
Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.
Explanation
This MCQ belongs to L27. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205A · Q8.
Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.
PYQ2. The hydrolysis of ethylene ozonide gives — (A) formaldehyde (B) acetaldehyde (C) acetone (D) ethene EWrbrZ AmoOmoZmBS>
Model Answer
Model approach (select the best option):
Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.
Explanation
This MCQ belongs to L27. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205B · Q13.
Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.
PYQ3. The hydrolysis of ethylene ozonide gives — (A) formaldehyde (B) acetaldehyde (C) acetone (D) ethene EWrbrZ AmoOmoZmBS>
Model Answer
Model approach (select the best option):
Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.
Explanation
This MCQ belongs to L27. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205C · Q2.
Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.
PYQ4. 1·22 g of benzoic acid is dissolved in 100 g of acetone (Kb for acetone is 1·7 K kg mol–1). The elevation in boiling point is 0·17 °C. Calculate the molar mass of benzoic acid. 1·22 J«m‘ ~ÝOmoBH$ Aåb
Model Answer
Answer using key concepts from L27 (definitions, equations, and one example where useful). Stay within the suggested word range for a 3-mark NIOS question.
Explanation
Cross-check with L27 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.
How to write for NIOS: Use 50–80 words with equation + reason. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205B · Q39 · 3 mark(s) · L27.
Six problems spanning this chapter’s NIOS syllabus. Every question is built from the notes and formula sheet: solve with equations first, then read the formal textbook-style write-up, the easy explanation, and the topic in depth (formulas, meaning, exam tips). If the question says draw, a labelled pencil sketch is provided. Explanations open by default.
Draw/label >C=O. Why is carbonyl carbon electrophilic?
Final answer: Cδ⁺ electrophilic
Oxygen withdraws electron density inductively/resonantly.
Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
Carbon of C=O is electron-poor—nucleophiles attack it.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
Aldehydes more reactive than ketones generally.
Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.
How is ethanal obtained from ethanol (mild oxidation)?
Final answer: Mild oxidation of ethanol
1° alcohol → aldehyde under controlled conditions.
Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
Stop at aldehyde before it becomes acid.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
Ketones from 2° alcohols.
Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.
Write the product type of HCN addition to carbonyl.
Final answer: Cyanohydrin
Nucleophilic addition is characteristic of aldehydes/ketones.
Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
CN⁻ attacks C=O then protonation gives HO–C–CN.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
Increases carbon chain by one.
Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.
What is required for aldol condensation?
Final answer: α-H containing carbonyl + base/acid
Enolate attacks another carbonyl carbon.
Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
Two molecules join; β-hydroxy carbonyl then may dehydrate.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
No α-H ⇒ no enolate (e.g. HCHO, benzaldehyde alone).
Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.
Why is ethanoic acid acidic?
Final answer: Resonance stabilised RCOO⁻
Carboxylic acids are stronger than alcohols/phenols generally.
Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
After losing H⁺, charge shares between two oxygens.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
Electron-withdrawing groups increase acidity.
Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.
Which test distinguishes aldehyde from ketone (simple)?
Final answer: Tollens’ or Fehling’s (aldehydes +)
Aldehydes easily oxidised; ketones resist under these conditions.
Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
Aldehyde reduces silver ion to shiny mirror.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
Aromatic aldehydes: Tollens may work; Fehling often not.
Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.