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Chemistry — Class 12 — L27: Aldehydes, Ketones and Carboxylic Acids

NIOS Code 313 · Module 7 · Chemistry of Organic Compounds

Notes extracted from NIOS Chemistry Course (313), Lesson 27 — Aldehydes, Ketones and Carboxylic Acids (313_Chemistry_Eng_Lesson27.pdf). Content covers sections 27.1–27.2.
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Overview — Carbonyl Compounds and Carboxylic Acids

Aldehydes (RCHO), ketones (R₂C=O) and carboxylic acids (RCOOH) contain the carbon–oxygen double bond. They flavour foods, serve as solvents and reagents, and are central to organic synthesis. This lesson covers nomenclature, preparation, polar C=O chemistry, nucleophilic addition, distinguishing tests, α-hydrogen reactions (aldol, haloform, Cannizzaro), and the preparation, acidity and reactions of carboxylic acids.

Section 1: Aldehydes and Ketones — Structure & Preparation (27.1)

Carbonyl C and O are sp² hybridised; molecule is planar about C=O. Oxygen is more electronegative → Cδ⁺=Oδ⁻. Carbon is electrophilic (Nu attack); oxygen is nucleophilic/basic (E⁺/H⁺). Dipole interactions raise b.p. vs hydrocarbons; H-bonding with water gives lower members good solubility.

Aldehydes more reactive than ketones: (i) only one +I alkyl group → more positive carbonyl C; (ii) less steric crowding.

Naming: alkanals (-al), alkanones (-one); common names acetone, acetophenone, benzaldehyde, formaldehyde. Carbonyl carbon gets lowest number; for ketones the -one suffix is numbered (propan-2-one). Aromatic aldehydes often keep common names (benzaldehyde).

Preparation (overview): oxidation of 1° alcohols → aldehydes (controlled, e.g. PCC or distillation of product); 2° alcohols → ketones (K₂Cr₂O₇/H⁺ or PCC); ozonolysis of alkenes (reductive work-up); hydration of alkynes (Hg²⁺/H⁺ → ethanal from ethyne, methyl ketones from terminal alkynes); Friedel–Crafts acylation (ArH + RCOCl/AlCl₃) → aromatic ketones; Rosenmund (RCOCl + H₂/Pd-BaSO₄ → RCHO — poisoned catalyst stops at aldehyde); Stephen reduction of nitriles (SnCl₂/HCl then H₃O⁺ → RCHO); dry distillation of calcium carboxylates for ketones (higher level).

Physical properties: lower aldehydes/ketones are liquids with characteristic odours. Boiling points higher than hydrocarbons of similar mass (dipole–dipole) but lower than alcohols (no O–H H-bonding between pure carbonyl molecules). Methanal, ethanal and propanone mix well with water; solubility falls as the hydrophobic R grows.

Polar Carbonyl Group Cδ⁺ =Oδ⁻ Nu attacks C E⁺ / H⁺ at O α-H acidic Three reactive sites · aldehyde more electrophilic than ketone
Polarisation of C=O drives almost all carbonyl chemistry.
Cδ⁺=Oδ⁻ + Nu⁻ → Nu–C–O⁻ → Nu–C–OH
Nucleophilic addition · tetrahedral intermediate · aldehydes faster than ketones

Section 2: Reactions of Aldehydes and Ketones (27.1.4)

A. Nucleophilic addition: HCN → cyanohydrins (useful C–C bond; hydrolyse to α-hydroxy acids); NaHSO₃ adducts (crystalline, reverse on acid/base); alcohols → hemiacetals then acetals (acid; protect carbonyls); water → gem-diols (hydrate, often reversible); Grignard → alcohols after acid work-up (HCHO → 1°, RCHO → 2°, R₂C=O → 3°); ammonia derivatives → imines, oximes, hydrazones, 2,4-DNP hydrazones (orange/yellow crystalline solids for m.p. identification of both aldehydes and ketones).

B. Reduction: to alcohols (NaBH₄ mild, LiAlH₄ stronger, catalytic H₂/Ni). Deoxygenation to alkanes: Wolff–Kishner (NH₂NH₂, KOH, high-boiling alcohol — base-compatible) vs Clemmensen (Zn-Hg/HCl — acid-compatible). Choose the method that does not destroy other acid- or base-sensitive groups.

C. Oxidation: aldehydes → carboxylic acids easily (even air, or KMnO₄/K₂Cr₂O₇). Tollen’s: ammoniacal AgNO₃, [Ag(NH₃)₂]⁺ → silver mirror. Fehling’s: Cu²⁺/tartrate alkaline → brick-red Cu₂O (aliphatic aldehydes; aromatic aldehydes often fail Fehling but give Tollen’s). Ketones resist these mild oxidants — classic distinction. Strong oxidants can still cleave ketones under forcing conditions (exam: mild tests are the focus).

Distinguishing Aldehydes from Ketones AldehydeTollen’s mirror · Fehling red KetoneNo Tollen’s/Fehling Both give 2,4-DNP ppt · only RCHO oxidises under mild conditions
Classic lab distinction based on ease of oxidation.
RCHO + [Ag(NH₃)₂]⁺ → RCOO⁻ + Ag⁰ (mirror)
Tollen’s test · selective for aldehydes

D. α-Carbon chemistry: α-H is acidic (enolate resonance) → keto–enol tautomerism. Halogenation at α-C (acid or base); excess base + I₂ → haloform (CHI₃ yellow ppt for methyl ketones CH₃COR and compounds oxidisable to them, e.g. ethanol, ethanal). Aldol: dilute NaOH on carbonyls with α-H → β-hydroxy aldehyde/ketone; heat drives dehydration to α,β-unsaturated carbonyl (conjugated). Crossed aldol needs care (one component without α-H preferred). Cannizzaro: aldehydes without α-H (HCHO, PhCHO) + concentrated NaOH → disproportionation: one molecule oxidised to acid salt, one reduced to alcohol. Never confuse: aldol needs α-H + dilute base; Cannizzaro needs no α-H + concentrated base.

α-Hydrogen Reactions Aldolneeds α-H · dil base HaloformCH₃COR · CHI₃ Cannizzarono α-H · conc base α-H present or absent decides the path
Three high-yield reactions controlled by α-hydrogen availability.
2CH₃CHO → CH₃CH(OH)CH₂CHO → CH₃CH=CHCHO
Aldol addition then condensation (dehydration)

Section 3: Carboxylic Acids (27.2)

RCOOH — formic, acetic, propanoic… alkanedioic acids (oxalic, malonic), benzoic acid and substituted aromatics. Carboxyl carbon is sp²; the –COOH group is planar. In pure liquids/solids, acids form strong H-bonded dimers → high melting and boiling points relative to alcohols of similar mass. Lower members are water-soluble; long-chain fatty acids are not.

Preparation: oxidation of alkenes (hot alkaline KMnO₄, cleaves double bond), 1° alcohols and aldehydes; side-chain oxidation of Ar–CH₃ (or longer alkyl) → ArCOOH (KMnO₄/H⁺ or CrO₃ — ring must have benzylic H); Grignard + CO₂ then acid work-up (adds one carbon); hydrolysis of nitriles and cyanohydrins (acid or base, then acidify). Industrial acetic acid: methanol carbonylation and related routes (context only).

RMgX + CO₂ → RCOOMgX → RCOOH  |  RCN + H₃O⁺ → RCOOH
Carbon chain lengthening routes to acids

Acidity: pKₐ typically ~4–5 in water. Dissociation gives resonance-stabilised carboxylate (negative charge shared by both oxygens) — much stronger acids than alcohols (pKₐ ~16) or phenols (pKₐ ~10). −I / electron-withdrawing substituents increase acidity (ClCH₂COOH > CH₃COOH; Cl₃CCOOH is very strong); alkyl groups slightly decrease acidity. Benzoic acid is a solid aromatic acid; o-substituents can affect strength via steric and electronic effects (exam: know the inductive trend first).

Carboxylate Resonance R–C(=O)–O⁻ R–C(O⁻)=O Charge shared · acids stronger than ROH/PhOH NaHCO₃ + RCOOH → CO₂↑ · phenols usually no fizz
Resonance stabilisation of RCOO⁻ underpins carboxylic acid strength.

Reactions: form salts with bases (NaOH, Na₂CO₃); liberate CO₂ from NaHCO₃/Na₂CO₃ (distinction from most phenols — phenols need stronger base); Fischer esterification with ROH/H⁺ (reversible; remove water to drive); form acid chlorides (SOCl₂ preferred — gaseous by-products; also PCl₅/PCl₃); amides via ammonium salt then heat dehydration; anhydrides by dehydrating agents or from RCOCl + RCOONa; reduction with LiAlH₄ → 1° alcohols (NaBH₄ usually does not reduce free RCOOH); α-halogenation (Hell–Volhard–Zelinsky) with X₂ and red phosphorus → α-halo acids for further substitution.

Derivatives: reactivity order roughly acid chloride > anhydride > ester > amide toward nucleophiles. Interconversions (e.g. RCOCl → ester or amide) are central to multi-step synthesis. Esters hydrolyse to acids (acid or base; base saponification is irreversible).

RCOOH + ROH ⇌ RCOOR′ + H₂O  |  RCOOH + SOCl₂ → RCOCl
Esterification equilibrium · acid chloride for further synthesis
Acid Strength Ladder ROH PhOH RCOOH Cl₃CCOOH −I groups increase carboxylic acidity
Relative acid strength — carboxylic acids between phenols and strong mineral acids.

Exam Connections and Chapter Summary

High-yield checklist: (1) polar C=O and why RCHO > R₂C=O (electronic + steric); (2) Nu addition products — cyanohydrin, acetal, oxime, 2,4-DNP; (3) Tollen’s/Fehling vs 2,4-DNP (oxidation vs carbonyl detection); (4) aldol needs α-H + dilute base, Cannizzaro needs no α-H + concentrated base; (5) iodoform for CH₃COR; (6) Wolff–Kishner (base) vs Clemmensen (acid) for C=O → CH₂; (7) acid preparation routes and pKₐ / −I trends; (8) NaHCO₃ CO₂ test vs phenols; (9) esterification and acid chlorides.

Builds on L26 (oxidation of alcohols to carbonyls and acids) and L25 (haloform chemistry). Next in the module: nitrogen compounds (L28) and biomolecules (L29). Practice writing the mechanism of nucleophilic addition and the aldol sequence — they appear repeatedly in board and competitive exams.

MCQ Quiz — L27 Aldehydes, Ketones and Carboxylic Acids

0 / 10 correct

Flashcards — L27

1 / 18

Golden Rules — L27 Aldehydes, Ketones and Carboxylic Acids

Most exam-important points from this chapter:

Carbonyl basics

C=O polar; Nu addition at C. Aldehydes > ketones. Name -al/-one.

Tests

2,4-DNP both. Tollen’s/Fehling aldehydes only. Iodoform for methyl ketones.

α-H chemistry

Aldol needs α-H. Cannizzaro needs no α-H. Haloform for CH₃COR.

Reduction

To alcohol (hydride/H₂). To alkane: Wolff–Kishner (base) or Clemmensen (acid).

Carboxylic acids

Stronger than ROH/PhOH (resonance). Prep: oxidation, RMgX+CO₂, RCN. NaHCO₃ fizz. Esters & RCOCl.

RCHO · R₂C=O
C=O polar · Nu addition
Aldehyde > ketone reactivity
Tollen’s · Fehling’s
Aldol · Cannizzaro
Haloform / iodoform
Wolff–Kishner · Clemmensen
RCOOH dimers · pKₐ ~5
RMgX + CO₂ → RCOOH

Section 1: Aldehydes & Ketones

NIOS Chemistry 313, Module 7 — Aldehydes, Ketones and Carboxylic Acids (sections 27.1–27.2).

Structure & Naming

Carbonyl C and O sp² · planar · Cδ⁺=Oδ⁻ · aldehydes more reactive than ketones (+I and steric)

IUPAC: alkanals (-al) · alkanones (-one) · benzaldehyde · propan-2-one (acetone)

Key Reactions of Carbonyls

Nu addition: HCN → cyanohydrin · NaHSO₃ · ROH → hemiacetal/acetal · RMgX → alcohol · NH₃ derivatives (oxime, hydrazone, 2,4-DNP)

Reduction: → alcohol · Wolff–Kishner (NH₂NH₂/base) · Clemmensen (Zn-Hg/HCl) → alkane

Oxidation: RCHO → RCOOH · Tollen’s [Ag(NH₃)₂]⁺ silver mirror · Fehling’s Cu₂O red ppt · ketones resist mild oxidants

α-H reactions: halogenation · haloform (CHI₃ test for methyl ketones) · aldol (dil. NaOH, needs α-H) · Cannizzaro (no α-H, conc. base)

Section 2: Carboxylic Acids

Preparation & Properties

Oxidation of alkenes, 1° ROH, RCHO · ArCH₃ + KMnO₄ → ArCOOH

RMgX + CO₂ → RCOOH · RCN + H₃O⁺ → RCOOH

H-bonded dimers · high b.p. · pKₐ ~4–5 · resonance-stabilised RCOO⁻

−I groups ↑ acidity (Cl₃CCOOH very strong) · alkyls slightly ↓ acidity

Acid Reactions & Derivatives

NaOH → salt · NaHCO₃ liberates CO₂ (test vs phenols) · ROH/H⁺ → ester · SOCl₂/PCl₅ → RCOCl

Reduction LiAlH₄ → 1° alcohol · Hell–Volhard–Zelinsky α-halogenation

Derivatives: acid chloride · ester · amide · anhydride (interconversions)

Section 2: Definitions

Carbonyl group: C=O; electrophilic carbon, nucleophilic oxygen.

Aldol condensation: α-H aldehyde/ketone + base → β-hydroxy carbonyl → α,β-unsaturated on heating.

Cannizzaro reaction: Aldehyde without α-H + conc. base → alcohol + carboxylate salt.

Tollen’s reagent: [Ag(NH₃)₂]⁺; oxidises aldehydes; silver mirror.

Carboxylate resonance: Charge shared by two oxygens — acids stronger than alcohols/phenols.

Section 3: Visual Map

L27 Map — Carbonyls & Acids RCHO / R₂C=O Nu add · α-H RCOOH Tollen’s · Fehling · aldol · Cannizzaro · haloform · RMgX+CO₂ Aldehyde oxidises · ketone resists · acid + NaHCO₃ → CO₂

Section 5: Q&A (12 Questions)

Q1: Why are aldehydes more reactive than ketones?

Less +I from one alkyl vs two; less steric hindrance at carbonyl C.

Q2: Product of CH₃CHO + HCN?

Acetaldehyde cyanohydrin CH₃CH(OH)CN.

Q3: Tollen’s test observation for ethanal?

Silver mirror; aldehyde oxidised to acetate; Ag⁺ reduced.

Q4: Fehling’s positive for?

Aliphatic aldehydes (brick-red Cu₂O); not usually ketones.

Q5: Aldol of ethanal?

3-Hydroxybutanal → on heat but-2-enal.

Q6: Cannizzaro substrate example?

HCHO or C₆H₅CHO (no α-H) + conc. NaOH → alcohol + salt of acid.

Q7: Iodoform from which carbonyls?

Methyl ketones CH₃COR and related CH₃CH(OH)R compounds.

Q8: Clemmensen vs Wolff–Kishner medium?

Clemmensen: Zn-Hg/HCl (acidic). Wolff–Kishner: NH₂NH₂/base (basic).

Q9: RMgX + CO₂ product after acid?

Carboxylic acid with one more carbon than R–X used for Grignard.

Q10: Why are carboxylic acids stronger than alcohols?

Carboxylate ion resonance-stabilised over two oxygens.

Q11: Effect of Cl on acetic acid acidity?

−I of Cl stabilises anion → chloroacetic acids stronger (Cl₃CCOOH strongest).

Q12: Distinguish RCOOH from PhOH with NaHCO₃?

Acids liberate CO₂; phenols usually do not (weaker acids).

Section 6: Tips & Exam Hacks

Memory Aids

  • Aldehyde vs ketone: "H makes it hotter (more reactive)"
  • Tollen’s: "Silver mirror = aldehyde"
  • Aldol: "Needs α-H + base"
  • Cannizzaro: "No α-H · one up one down"
  • NaHCO₃: "Fizz for carboxylic acids"

Exam Tips

  • 2,4-DNP gives yellow/orange ppt for both RCHO and R₂C=O
  • Only aldehydes give Tollen’s/Fehling
  • Write enolate for α-H chemistry
  • Carboxylic acids form H-bonded dimers
  • Esterification is equilibrium (remove H₂O)

Section 8: Quick Reference

• C=O polar · Nu at C · E⁺ at O · aldehyde > ketone

• Additions: HCN, ROH, RMgX, NH₂ derivatives

• Tests: Tollen’s, Fehling, 2,4-DNP, iodoform

• Aldol (α-H) · Cannizzaro (no α-H) · haloform

• RCOOH: prep, acidity, salts, esters, RCOCl

PYQ — Previous Year Questions

Extracted from NIOS Chemistry (313) board exam papers in your PDF. Chapter L27 — Aldehydes, Ketones and Carboxylic Acids only. Use Model Answer for marking points; Explanation for concept clarity.

L27 — Aldehydes, Ketones and Carboxylic Acids

4 question(s) · Sources: 313/MAY/205A, 313/MAY/205B, 313/MAY/205C

Section A — MCQ / Objective (from papers)

PYQ1. The hydrolysis of ethylene ozonide gives — (A) formaldehyde   (B) acetaldehyde   (C) acetone   (D) ethene EWrbrZ AmoOmoZmBS>

1 mark · Q8 · 313/MAY/205A

Model Answer

Model approach (select the best option):

  • (A) formaldehyde
  • (B) acetaldehyde
  • (C) acetone
  • (D) ethene EWrbrZ AmoOmoZmBS>

Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.

Explanation

This MCQ belongs to L27. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205A · Q8.

Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.

PYQ2. The hydrolysis of ethylene ozonide gives — (A) formaldehyde   (B) acetaldehyde   (C) acetone   (D) ethene EWrbrZ AmoOmoZmBS>

1 mark · Q13 · 313/MAY/205B

Model Answer

Model approach (select the best option):

  • (A) formaldehyde
  • (B) acetaldehyde
  • (C) acetone
  • (D) ethene EWrbrZ AmoOmoZmBS>

Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.

Explanation

This MCQ belongs to L27. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205B · Q13.

Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.

PYQ3. The hydrolysis of ethylene ozonide gives — (A) formaldehyde   (B) acetaldehyde   (C) acetone   (D) ethene EWrbrZ AmoOmoZmBS>

1 mark · Q2 · 313/MAY/205C

Model Answer

Model approach (select the best option):

  • (A) formaldehyde
  • (B) acetaldehyde
  • (C) acetone
  • (D) ethene EWrbrZ AmoOmoZmBS>

Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.

Explanation

This MCQ belongs to L27. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205C · Q2.

Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.

Section B — Short / Long answer (from papers)

PYQ4. 1·22 g of benzoic acid is dissolved in 100 g of acetone (Kb for acetone is 1·7 K kg mol–1). The elevation in boiling point is 0·17 °C. Calculate the molar mass of benzoic acid. 1·22 J«m‘ ~ÝOmoBH$ Aåb

3 marks · Q39 · 313/MAY/205B

Model Answer

Answer using key concepts from L27 (definitions, equations, and one example where useful). Stay within the suggested word range for a 3-mark NIOS question.

Explanation

Cross-check with L27 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.

How to write for NIOS: Use 50–80 words with equation + reason. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205B · Q39 · 3 mark(s) · L27.

Problem Solving — L27 Aldehydes, Ketones and Carboxylic Acids

Six problems spanning this chapter’s NIOS syllabus. Every question is built from the notes and formula sheet: solve with equations first, then read the formal textbook-style write-up, the easy explanation, and the topic in depth (formulas, meaning, exam tips). If the question says draw, a labelled pencil sketch is provided. Explanations open by default.

Question 1 of 6Carbonyl

Draw/label >C=O. Why is carbonyl carbon electrophilic?

Pencil sketch (labelled)

Key functional groups —OH alcohol / phenol —CHO aldehyde >C=O ketone —COOH carboxylic acid —NH₂ amine
Pencil sketch: common organic groups

Solution — step by step with formulas

  1. Polar Cδ⁺=Oδ⁻; carbon attacked by nucleophiles.

Final answer: Cδ⁺ electrophilic

Textbook formal language

Oxygen withdraws electron density inductively/resonantly.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

Carbon of C=O is electron-poor—nucleophiles attack it.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — Carbonyl group

Aldehydes more reactive than ketones generally.

Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.
Question 2 of 6Prep

How is ethanal obtained from ethanol (mild oxidation)?

Solution — step by step with formulas

  1. Controlled oxidation (PCC / hot Cu / acid dichromate carefully).

Final answer: Mild oxidation of ethanol

Textbook formal language

1° alcohol → aldehyde under controlled conditions.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

Stop at aldehyde before it becomes acid.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — From alcohols

Ketones from 2° alcohols.

Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.
Question 3 of 6Nucleophilic

Write the product type of HCN addition to carbonyl.

Solution — step by step with formulas

  1. Cyanohydrin.

Final answer: Cyanohydrin

Textbook formal language

Nucleophilic addition is characteristic of aldehydes/ketones.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

CN⁻ attacks C=O then protonation gives HO–C–CN.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — Addition reactions

Increases carbon chain by one.

Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.
Question 4 of 6Aldol

What is required for aldol condensation?

Solution — step by step with formulas

  1. Carbonyl with α-hydrogen; base/acid catalysed.

Final answer: α-H containing carbonyl + base/acid

Textbook formal language

Enolate attacks another carbonyl carbon.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

Two molecules join; β-hydroxy carbonyl then may dehydrate.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — Aldol condensation

No α-H ⇒ no enolate (e.g. HCHO, benzaldehyde alone).

Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.
Question 5 of 6Carboxyl

Why is ethanoic acid acidic?

Solution — step by step with formulas

  1. Resonance stabilised acetate ion after loss of H⁺.

Final answer: Resonance stabilised RCOO⁻

Textbook formal language

Carboxylic acids are stronger than alcohols/phenols generally.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

After losing H⁺, charge shares between two oxygens.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — Acidity of RCOOH

Electron-withdrawing groups increase acidity.

Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.
Question 6 of 6Test

Which test distinguishes aldehyde from ketone (simple)?

Solution — step by step with formulas

  1. Tollens’ (silver mirror) or Fehling’s (red ppt) — aldehydes positive.

Final answer: Tollens’ or Fehling’s (aldehydes +)

Textbook formal language

Aldehydes easily oxidised; ketones resist under these conditions.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

Aldehyde reduces silver ion to shiny mirror.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — Tollens / Fehling

Aromatic aldehydes: Tollens may work; Fehling often not.

Linked to chapter notes (L27). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.