313_Chemistry_Eng_Lesson2.pdf). Content covers sections 2.1–2.11.Chemistry is defined as the study of matter in terms of its structure, composition and properties. Matter is made up of atoms, and therefore an understanding of the internal structure of the atom is fundamental to chemistry. Ancient Indian and Greek philosophers (600–400 BC) proposed the earliest concept of the atom as the smallest indivisible part of matter — without experimental evidence, based on thought experiments about continuous subdivision. John Dalton revived the atomic concept in the nineteenth century through his atomic theory, which explained the laws of chemical combination. Later experiments showed that the atom is not indivisible but possesses an internal structure.
In this lesson you will learn about the internal structure of an atom, which helps you understand correlations between structure and properties studied in later lessons. Topics span fundamental particles, atomic and mass numbers, isotopes, historical atomic models (Thomson, Rutherford, Bohr), electromagnetic radiation, the hydrogen line spectrum, wave–particle duality, Heisenberg's uncertainty principle, the quantum mechanical model, quantum numbers, orbital shapes, and rules for electronic configuration including the stability of half-filled and completely filled subshells.
In 1897, J.J. Thomson discovered the electron as a constituent of the atom. He determined that an electron carries a negative charge and has very little mass compared to the whole atom. Since atoms are electrically neutral, a source of positive charge must exist within the atom. This led to the experimental discovery of the proton — a positively charged subatomic particle approximately 1840 times heavier than an electron.
Further experiments revealed that atomic masses exceeded what protons and electrons alone could account for. For example, helium's mass was expected to be double hydrogen's but was found to be almost four times greater. This suggested neutral particles with mass comparable to protons. In 1932, Sir James Chadwick discovered the neutron. Atoms are therefore composed of three fundamental particles:
Because atoms contain still smaller particles, they must have an internal structure — the subject of the rest of this chapter. Comparing masses: an electron is about 1/1840 the mass of a proton, yet both are dwarfed by the atom as a whole because most atomic mass resides in the nucleus (protons + neutrons). This mass discrepancy for helium (four times hydrogen, not twice) was the crucial clue that forced scientists beyond the proton–electron picture.
All atoms are identified by the number of protons and neutrons they contain. The atomic number (Z) is the number of protons in the nucleus of each atom of an element. In a neutral atom, protons equal electrons, so Z also gives the electron count. Chemical identity depends solely on Z — every atom with 7 protons is nitrogen.
The mass number (A) is the total number of protons and neutrons in the nucleus: A = Z + N, where N is the number of neutrons. Except for ordinary hydrogen (one proton, no neutrons), all nuclei contain both protons and neutrons. Neutrons = A − Z. For fluorine (A = 19, Z = 9), neutrons = 10.
Atoms of the same element can differ in mass. Most elements have isotopes — same Z, different A. Hydrogen has three isotopes: ¹H (protium, 0 neutrons), ²H (deuterium, 1 neutron), ³H (tritium, 2 neutrons). Uranium-235 and uranium-238 share Z = 92 but differ in properties — U-235 is used in reactors; U-238 lacks those properties. Isotopes are named by mass number (except hydrogen's special names). Chemical properties depend on protons and electrons; neutrons do not participate in ordinary chemical change, so isotopes of an element have similar chemistry.
Isobars are atoms of different elements with the same mass number A but different Z — for instance ⁴⁰Ar₁₈ and ⁴⁰Ca₂₀ both have A = 40 but are different elements. Do not confuse isotopes (same Z) with isobars (same A).
Isotope notation places mass number A as superscript and atomic number Z as subscript on the element symbol X. Hydrogen isotopes are written ¹H₁, ²H₁, ³H₁ (protium, deuterium, tritium). For uranium: ²³⁵U₉₂ versus ²³⁸U₉₂ — same chemistry (both uranium) but very different nuclear behaviour. Example 2.1: In ¹⁷O₈: 8 protons, 9 neutrons, 8 electrons. In ¹⁹⁹Hg₈₀: 80 protons, 119 neutrons, 80 electrons. ²⁰⁰Hg₈₀ is a chemically similar isotope with 120 neutrons. All three values Z, N and A must be positive integers.
After establishing that atoms are divisible, scientists proposed models for internal structure. J.J. Thomson, from discharge tube experiments, suggested atoms as a large positively charged body with small negative electrons scattered throughout — the plum pudding model (electrons = plums in positive pudding) or watermelon model (pulp = positive charge, seeds = electrons).
Ernest Rutherford tested Thomson's model with the α-ray scattering experiment (1908 Nobel Prize in Chemistry). A beam of fast-moving α-particles (He²⁺ ions) passed through very thin gold foil. Most particles passed straight through, but some were deflected — a few through large angles, and about 1 in 10,000 rebounded.
Rutherford's conclusions: (1) Atom contains a dense, positively charged nucleus at the centre. (2) Nearly all positive charge and mass reside in the nucleus. (3) Remaining volume is mostly empty space containing small negative electrons.
Rutherford's model explained scattering data elegantly: undeflected α-particles pass through empty space; near-miss deflections occur when α-particles approach the nucleus; direct collision causes rebound. Yet the model could not explain why electrons do not radiate while orbiting.
Failure of Rutherford's model: Maxwell's electromagnetic theory states that an accelerating charged particle radiates energy continuously. An orbiting electron is accelerating (centripetal force) and should continuously lose energy, spiralling inward (Fig. 2.5) until the atom collapses in about 10⁻⁸ s — but atoms are stable and emit line spectra, not continuous radiation. This contradiction motivated Niels Bohr, a student of Rutherford, to introduce quantisation of electron energy in 1913.
Before explaining atomic spectra, we need electromagnetic radiation (EMR). EMR is energy transmitted through space as oscillating electric and magnetic fields perpendicular to each other and to the direction of propagation — no medium required. Examples: visible light, heat, radio waves, X-rays, gamma rays. EMR travels at c = 3.0 × 10⁸ m s⁻¹ in vacuum.
EM radiation also exhibits particle nature. Energy is carried in bundles called quanta; a quantum of visible light is a photon. Photon energy is proportional to frequency:
Example 2.2: 12 GHz microwave: E = 6.626×10⁻³⁴ × 1.2×10¹⁰ = 7.95×10⁻²⁴ J. Example 2.3: Green light λ = 535 nm: E = hc/λ = 3.71×10⁻¹⁹ J.
The electromagnetic spectrum spans radio waves through gamma rays; visible light is a tiny portion (Fig. 2.7). Radiation with shorter wavelength (higher frequency) carries more energy per photon — gamma rays at one extreme, radio waves at the other. Wave number ν̄ is especially convenient in spectroscopy because it is directly proportional to energy: E = hcν̄.
Quantisation of energy was revolutionary: unlike classical waves that can have any energy, photons come in discrete packets proportional to ν. This particle picture complements the wave picture — together they foreshadow the wave–particle duality developed later in this chapter.
Sunlight through a prism gives a continuous spectrum (VIBGYOR) — wavelengths vary without break. Flame tests (Na = yellow, Cu = green, Sr = crimson) produce light that, when passed through a prism, splits into discrete lines — a line spectrum (Fig. 2.8).
Electric discharge through low-pressure H₂ emits light that forms discrete lines in UV, visible and IR. The general Rydberg formula:
Named series (Table 2.2): Lyman (UV, n₁=1, n₂=2,3,4…), Balmer (visible, n₁=2, n₂=3,4,5…), Paschen (IR, n₁=3), Brackett (IR, n₁=4), Pfund (IR, n₁=5). Johann Balmer first found a simple formula for visible lines. Example 2.4: For Balmer n₂=3: ν̄ = 109677(1/4 − 1/9) = 109677 × 5/36 cm⁻¹; λ = 1/ν̄ = 656 nm (red line). The discrete lines prove that electron energies in hydrogen are quantised, not continuous.
Niels Bohr proposed electrons moving in definite circular orbits around the nucleus. Postulates:
Bohr explained the hydrogen line spectrum: transitions between stationary states give hν = Ei − Ef, yielding the Rydberg formula when combined with En = −RH/n². Energy levels are inversely proportional to n² — E₁ is most negative (most stable); as n increases, energy approaches zero (ionisation limit). Bohr correlated RH to fundamental constants: RH = mez²e⁴/(8ε₀²h³) for nuclear charge z (Z for hydrogen).
Bohr won the 1922 Nobel Prize in Physics. His model was a landmark but limited: it works well for one-electron species (H, He⁺, Li²⁺) but fails for multi-electron atoms (no account of electron–electron repulsion), cannot explain fine structure (multiple closely spaced lines), Zeeman effect (magnetic field splitting) or the varying intensities of spectral lines. These failures pointed toward a more complete quantum mechanical treatment.
Light shows both wave properties (diffraction, interference) and particle properties (photoelectric effect). In 1923, Louis de Broglie proposed that matter particles also have wave nature. A particle of mass m and velocity v has wavelength:
Example 2.5: A 380 g cricket ball at 140 km/h (38.89 m s⁻¹) has λ = h/(mv) ≈ 4.48×10⁻³⁵ m — far too small to measure. Electrons, with tiny mass, have measurable wavelengths. In 1927, G.P. Thomson and C.J. Davisson demonstrated electron diffraction by nickel crystals (Fig. 2.13) — the diffraction pattern proved electrons behave as waves under appropriate conditions. de Broglie received the 1929 Nobel Prize in Physics for his 1924 PhD thesis proposing this duality.
Wave–particle duality is not contradiction but complementarity: diffraction and interference demand wave models; photoelectric effect and α-scattering demand particle models. The same electron can display either behaviour depending on the experiment.
Wave–particle duality implies we cannot simultaneously measure position and momentum of an electron with perfect precision:
If Δx = 0 (electron located exactly), Δp → ∞ (momentum completely unknown). Conversely, precise momentum means position is entirely uncertain. In practice both have finite uncertainty. Because h = 6.626×10⁻³⁴ J s is extraordinarily small, the principle is negligible for cars, cricket balls and aeroplanes — but dominant for electrons.
Heisenberg (Nobel Prize 1932) showed Bohr's simultaneous exact radius and velocity for each orbit is impossible. You cannot trace a definite path for an electron; only speak of probability of finding it in a region. This directly motivated Schrödinger's wave mechanical model replacing orbits with orbitals.
Erwin Schrödinger (1926) proposed the wave mechanical model. Electron motion is described by a wave function ψ obtained from the Schrödinger wave equation (SWE). |ψ|² gives the probability of finding the electron in 3D space around the nucleus. The region of maximum probability is an atomic orbital — not a fixed path (orbit) but a probability cloud.
Each electron has a unique set of four quantum numbers:
1s orbital: radial probability peaks at 52.9 pm for H; boundary surface encloses 95% probability — drawn as a sphere. 2s orbital: larger sphere with one spherical node (region of zero probability). Number of spherical nodes = n − l − 1. A nodal plane is a flat region of zero probability (p orbitals have one nodal plane). 3s has 2 spherical nodes.
Orbit vs orbital: Bohr's circular path = orbit (definite trajectory). Quantum orbital = 3D probability region — no fixed path. The wave function ψ itself has no direct physical meaning; only |ψ|² (probability density) is observable.
For n = 3 shell, Table 2.3 lists all allowed combinations: l = 0 (one 3s), l = 1 (three 3p with ml = −1,0,+1), l = 2 (five 3d). Each orbital holds max 2 electrons (Pauli), giving 2 + 6 + 10 = 18 total — matching 2n² = 2(9) = 18. Every electron in the atom has a unique set of four quantum numbers — no two electrons are identical in all four.
px, py, pz differ in orientation (ml) but have equal energy in the absence of external fields (degenerate). Five d orbitals (dxy, dyz, dxz, dx²−y², dz²) are also degenerate. Nodal planes in p and d orbitals arise where wave function changes sign — zero probability of finding the electron in that plane.
Electrons fill orbitals in order of increasing energy so the atom has minimum energy. For multi-electron atoms, use the (n + l) rules:
Order: 1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s …
No two electrons in an atom can have all four quantum numbers identical. Since three quantum numbers define an orbital, only two electrons per orbital with opposite spins (+½ and −½).
Electrons occupy degenerate orbitals singly with parallel spins before pairing. Carbon: 1s² 2s² 2px¹ 2py¹ 2pz⁰ (not paired in one p orbital). Electrons repel — they spread across orbitals.
Notation methods: superscript (1s² 2s² 2p¹x 2p¹y 2p¹z for N) and orbital box diagram with ↑↓ arrows. Shorthand: [He] 2s¹ for Li; core electrons in noble gas brackets, valence electrons outside.
Aufbau sometimes fails when subshell energies are close (4s/3d, 5s/4d). Chromium: predicted [Ar] 4s² 3d⁴, actual [Ar] 4s¹ 3d⁵. Copper: predicted 3d⁹ 4s², actual 3d¹⁰ 4s¹. Reasons:
These exceptions are exam favourites — memorise Cr and Cu configurations. Similar reasoning applies to other half-filled d⁵ and fully-filled d¹⁰ cases (e.g. Mo, Ag) though NIOS highlights Cr and Cu specifically.
Electronic configuration determines valence electrons and hence chemical behaviour. Core electrons ([noble gas] configuration) are buried in inner shells; valence electrons participate in bonding. Nitrogen 1s² 2s² 2px¹ 2py¹ 2pz¹ has 5 valence electrons (2s + 2p); lithium [He] 2s¹ has 1. Understanding filling order explains periodic trends studied in later modules.
Intext checkpoints from the textbook reinforce key skills: comparing e⁻ and p⁺ masses (Intext 2.1), listing Rutherford conclusions (2.2), computing photon energies (2.3–2.4), distinguishing line vs continuous spectra (2.4), calculating de Broglie λ for electrons (2.5), defining wave function and quantum numbers (2.6), counting spherical nodes in 3s (answer: 2, from n−l−1 = 3−0−1) (2.7), and applying (n+l) rules to decide 4s before 3d (2.8).
Atoms contain electrons, protons and neutrons. Z defines the element; isotopes share Z but differ in N. Thomson's plum pudding gave way to Rutherford's nuclear model, which failed on stability. Bohr quantised orbits and explained the H spectrum via E = hν and En = −RH/n². de Broglie and Heisenberg established wave–particle duality and uncertainty, leading to Schrödinger's quantum model with orbitals defined by quantum numbers n, l, ml, ms. Electron filling follows Aufbau, Pauli and Hund's rules, with Cr and Cu as notable exceptions due to half-filled/full d-subshell stability.
Most exam-important points from this chapter:
Atom = electrons (−1), protons (+1), neutrons (0). Proton mass ≈ 1840 × electron. Chadwick discovered neutron (1932).
Z = protons = electrons (neutral). A = Z + N. Isotopes: same Z, different N. Chemistry depends on Z, not N.
Rutherford: nucleus proved by α-scattering but electron should spiral in (Maxwell). Bohr: quantised orbits + photon transitions fix H spectrum.
c = νλ links wave properties; E = hν links particle properties. Know Rydberg for H lines: Balmer = visible (n₁=2).
Aufbau (n+l), Pauli (max 2 e⁻/orbital, opposite spin), Hund (single occupancy first). Cr = 3d⁵ 4s¹, Cu = 3d¹⁰ 4s¹ — half/full d stability.
Extracted from NIOS Chemistry (313) board exam papers in your PDF. Chapter L2 — Atomic Structure only. Use Model Answer for marking points; Explanation for concept clarity.
10 question(s) · Sources: 313/MAY/205A, 313/MAY/205B, 313/MAY/205C, 313/TUS/105A
PYQ1. 1 a.m.u. is equal to — (A) 12 th of mass of one C–12 atom (B) 14 th of mass of one C–12 atom (C) 16 th of mass of one O–16 atom (D) mass of one H atom 1 a.m.u
Model Answer
Model approach (select the best option):
Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.
Explanation
This MCQ belongs to L2. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205A · Q2.
Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.
PYQ2. Which statement is not correct about quantum? — (A) It is a bundle of energy (B) A quantum of visible light is called a photon (C) The energy of the quantum is proportional to the frequency of the radiation (D) The energy of the quantum is proportional to the wavelength of the radiation. ¹
Model Answer
Model approach (select the best option):
Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.
Explanation
This MCQ belongs to L2. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205A · Q4.
Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.
PYQ3. Read the passage given below and answer the following questions : Electromagnetic radiations travel with the velocity of light. These do not require any medium to propagate. These travel as waves in the planes perpendicular to each other and also to the direction of propagation. Depict the amplitude and wavelength () of an electromagnetic wave in the form of a diagram. Define a photon. Give its mathematical expression.
Model Answer
State the precise definition from the L2 notes in 1–2 sentences, include formula/example if marks ≥ 2, and avoid extra theory beyond the ask.
Explanation
Definition questions score for accuracy of wording + one supporting point/example. Do not write full chapter summaries.
How to write for NIOS: Use 30–50 words (VSA) or short objective. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205A · Q18 · 2 mark(s) · L2.
PYQ4. 1 a.m.u. is equal to — (A) 12 th of mass of one C–12 atom (B) 14 th of mass of one C–12 atom (C) 16 th of mass of one O–16 atom (D) mass of one H atom 1 a.m.u
Model Answer
Model approach (select the best option):
Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.
Explanation
This MCQ belongs to L2. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205B · Q9.
Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.
PYQ5. Which statement is not correct about quantum? — (A) It is a bundle of energy (B) A quantum of visible light is called a photon (C) The energy of the quantum is proportional to the frequency of the radiation (D) The energy of the quantum is proportional to the wavelength of the radiation. ¹
Model Answer
Model approach (select the best option):
Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.
Explanation
This MCQ belongs to L2. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205B · Q10.
Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.
PYQ6. Read the passage given below and answer the following questions : Electromagnetic radiations travel with the velocity of light. These do not require any medium to propagate. These travel as waves in the planes perpendicular to each other and also to the direction of propagation. Depict the amplitude and wavelength () of an electromagnetic wave in the form of a diagram. Define a photon. Give its mathematical expression.
Model Answer
State the precise definition from the L2 notes in 1–2 sentences, include formula/example if marks ≥ 2, and avoid extra theory beyond the ask.
Explanation
Definition questions score for accuracy of wording + one supporting point/example. Do not write full chapter summaries.
How to write for NIOS: Use 30–50 words (VSA) or short objective. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205B · Q20 · 2 mark(s) · L2.
PYQ7. 1 a.m.u. is equal to — (A) 12 th of mass of one C–12 atom (B) 14 th of mass of one C–12 atom (C) 16 th of mass of one O–16 atom (D) mass of one H atom 1 a.m.u
Model Answer
Model approach (select the best option):
Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.
Explanation
This MCQ belongs to L2. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205C · Q7.
Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.
PYQ8. Which statement is not correct about quantum? — (A) It is a bundle of energy (B) A quantum of visible light is called a photon (C) The energy of the quantum is proportional to the frequency of the radiation (D) The energy of the quantum is proportional to the wavelength of the radiation. ¹
Model Answer
Model approach (select the best option):
Eliminate options that contradict definitions/equations from the chapter notes. NIOS awards full mark for the single correct choice.
Explanation
This MCQ belongs to L2. Recall the core definition or formula from notes, then match it to one option. Paper: 313/MAY/205C · Q8.
Tip: For numerical MCQs, write the formula first, substitute values, then pick the option.
PYQ9. Read the passage given below and answer the following questions : Electromagnetic radiations travel with the velocity of light. These do not require any medium to propagate. These travel as waves in the planes perpendicular to each other and also to the direction of propagation. Depict the amplitude and wavelength () of an electromagnetic wave in the form of a diagram. Define a photon. Give its mathematical expression.
Model Answer
State the precise definition from the L2 notes in 1–2 sentences, include formula/example if marks ≥ 2, and avoid extra theory beyond the ask.
Explanation
Definition questions score for accuracy of wording + one supporting point/example. Do not write full chapter summaries.
How to write for NIOS: Use 30–50 words (VSA) or short objective. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205C · Q23 · 2 mark(s) · L2.
PYQ10. Draw the shapes of d-orbitals. d-H$jH$m|
Model Answer
Answer using key concepts from L2 (definitions, equations, and one example where useful). Stay within the suggested word range for a 2-mark NIOS question.
Explanation
Cross-check with L2 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.
How to write for NIOS: Use 30–50 words (VSA) or short objective. Open with definition/equation, then reason, end with conclusion. Paper 313/TUS/105A · Q30 · 2 mark(s) · L2.
Six problems spanning this chapter’s NIOS syllabus. Every question is built from the notes and formula sheet: solve with equations first, then read the formal textbook-style write-up, the easy explanation, and the topic in depth (formulas, meaning, exam tips). If the question says draw, a labelled pencil sketch is provided. Explanations open by default.
State Bohr’s angular momentum quantisation. Write ground-state energy of H atom. Draw a sketch of n=1,2,3 orbits.
Final answer: L = nh/2π; E₁ = −13.6 eV
Bohr assumed stationary orbits with quantised angular momentum; hydrogen energies follow E_n = −13.6/n² eV.
Working formulas: mvr = nh/2π; E_n = −13.6/n² eV (H). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
Only certain circular orbits allowed; lowest hydrogen energy is −13.6 eV.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
Explains line spectrum via ΔE = hf between levels.
Linked to chapter notes (L2). Remember: mvr = nh/2π; E_n = −13.6/n² eV (H). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write mvr = nh/2π; E_n = −13.6/n² eV (H) before substituting. Keep three significant figures until the end when data allow.
List the four quantum numbers and state what each describes.
Final answer: n, l, m_l, m_s as above
Four quantum numbers uniquely label an electron in an atom (Pauli framework).
Working formulas: n, l, m_l, m_s. State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
n = which floor; l = room shape; m_l = which door; m_s = spin up/down.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
l = 0…n−1; m_l = −l…+l; m_s = ±½.
Linked to chapter notes (L2). Remember: n, l, m_l, m_s. Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write n, l, m_l, m_s before substituting. Keep three significant figures until the end when data allow.
How many orbitals are in a p subshell? Maximum electrons in 3p?
Final answer: 3 orbitals; 6 electrons
Subshell capacity is 2(2l+1) electrons.
Working formulas: s: 1 orbital; p: 3; d: 5. State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
Three p boxes, two electrons each → six.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
3p means n=3, l=1.
Linked to chapter notes (L2). Remember: s: 1 orbital; p: 3; d: 5. Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write s: 1 orbital; p: 3; d: 5 before substituting. Keep three significant figures until the end when data allow.
Write the electronic configuration of ₇N and explain Hund’s rule for 2p.
Final answer: 1s² 2s² 2p³; parallel spins in 2p
Hund’s rule: degenerate orbitals fill singly with parallel spin before pairing.
Working formulas: Aufbau, Pauli, Hund. State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
Don’t pair p electrons until each p orbital has one—like seats on a bus.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
Pauli: no two electrons share all four quantum numbers.
Linked to chapter notes (L2). Remember: Aufbau, Pauli, Hund. Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write Aufbau, Pauli, Hund before substituting. Keep three significant figures until the end when data allow.
Name the series for transitions ending at n=2.
Final answer: Balmer series
Discrete lines arise from electronic transitions between Bohr levels.
Working formulas: 1/λ = R(1/n₁² − 1/n₂²). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
Jumps down to level 2 make the coloured Balmer lines.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
Lyman → n=1 (UV); Paschen → n=3 (IR).
Linked to chapter notes (L2). Remember: 1/λ = R(1/n₁² − 1/n₂²). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write 1/λ = R(1/n₁² − 1/n₂²) before substituting. Keep three significant figures until the end when data allow.
State de Broglie’s relation for a material particle.
Final answer: λ = h/p
Matter waves have wavelength h/p; supported Bohr quantisation via standing waves.
Working formulas: λ = h/p. State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.
Faster/heavier particles have shorter wavelengths.
Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.
Electron diffraction confirms wave nature of electrons.
Linked to chapter notes (L2). Remember: λ = h/p. Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.
Write λ = h/p before substituting. Keep three significant figures until the end when data allow.