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Chemistry — Class 12 — L19: p-Block Elements and Their Compounds-I

NIOS Code 313 · Module 6 · Chemistry of Elements

Notes extracted from NIOS Chemistry Course (313), Lesson 19 — p-Block Elements and Their Compounds-I (313_Chemistry_Eng_Lesson19.pdf). Content covers sections 19.1–19.6.
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Overview — p-Block Compounds I (Groups 13–15)

Lesson 18 gave general p-block trends. This lesson develops important compounds of Groups 13, 14 and 15: boric acid, borax, diborane, BF₃, AlCl₃ and alums; carbon allotropes, CO/CO₂/SiO₂, CCl₄ vs SiCl₄, SiC, silicones, silicates and zeolites; nitrogen, ammonia (Haber), nitric acid (Ostwald), phosphorus allotropes and halides, and fertilizers. Groups 16–18 follow in L20.

Key themes: electron-deficient bonding (B, Al), catenation (C), empty d-orbitals (Si, P), industrial processes (Haber, Ostwald), and materials (diamond, graphite, silicones, fertilizers).

Section 1: Group 13 — General & Boron/Aluminium Compounds (19.1–19.2)

Group 13: B, Al, Ga, In, Tl. Valency three, but anhydrous compounds are largely covalent — removing three electrons costs huge energy (B never forms B³⁺). B is non-metallic; Al metallic; Ga–Tl weakly metallic. Inert pair makes Tl⁺ important (L18). Al is the most abundant metal in Earth’s crust; main ore bauxite. Boron occurs as borax and kernite.

Group 13 Highlights Boron Non-metal · electron deficient borax, H₃BO₃, B₂H₆ Aluminium Metal · bauxite Al₂Cl₆ · alum Ga, In, Tl Weak metals Tl⁺ inert pair Compounds largely covalent when anhydrous
Boron and aluminium dominate exam chemistry of Group 13 compounds.

19.2.1–19.2.2 Boric Acid and Borax

Boric acid H₃BO₃ from borax + H₂SO₄: Na₂B₄O₇ + H₂SO₄ + 5H₂O → Na₂SO₄ + 4H₃BO₃. Weak Lewis acid: B(OH)₃ + 2H₂O → [B(OH)₄]⁻ + H₃O⁺. Structure: 2D sheets of B(OH)₃ units linked by H-bonds; layers held by van der Waals — flakes. Heat → metaboric acid → B₂O₃. Uses: antiseptic, food preservative, enamels and glass.

Borax Na₂B₄O₇·10H₂O (tincal; from colemanite + Na₂CO₃). Flux, buffer in dyeing, optical/borosilicate glass, glazes, preservative. Loses water of crystallisation on heating.

B(OH)₃ + 2H₂O → [B(OH)₄]⁻ + H₃O⁺
Boric acid is a Lewis acid (accepts OH⁻), not a simple protonic acid

19.2.3 Diborane B₂H₆

Prepared from BCl₃ + LiAlH₄ or BF₃ + LiH. Toxic, foul-smelling gas; burns with huge heat (ΔH = −1976 kJ mol⁻¹); hydrolyses to boric acid + H₂.

Structure: 4 terminal H and 2 B in a plane; 2 bridging H above and below. Only 12 valence electrons for eight B–H contacts → four normal 2c–2e B–H bonds + two 3c–2e (banana) B–H–B bridges. Classic electron-deficient bonding. Terminal B–H ~119 pm; bridge bonds longer (~134 pm) — weaker multi-centre links.

Al becomes passive after conc. HNO₃ because a thin Al₂O₃ film seals the surface — same idea as Be’s oxide film (L17). Always distinguish anhydrous AlCl₃ (covalent dimer, catalyst) from aqueous aluminium chemistry (hydrated ions).

Diborane — Bridge Bonds B B H H Green H = 3c–2e bridges · Red H = terminal 2c–2e
Diborane: electron-deficient 3-centre 2-electron bridge bonds.

19.2.4–19.2.6 BF₃, AlCl₃, Alums

BF₃ from B₂O₃ + HF. Incomplete octet → Lewis acid; complexes F₃B←NH₃, F₃B←OEt₂. Resonance shortens B–F. Catalyst in Friedel–Crafts and polymerisation. Hydrolyses: 4BF₃ + 3H₂O → H₃BO₃ + 3HBF₄.

AlCl₃ as Al₂Cl₆ dimer at room temperature (Cl bridges complete Al octets; roughly tetrahedral about each Al). Made from Al + Cl₂ or HCl. Sublimes; with water gives [Al(H₂O)₆]³⁺. Anhydrous form: Friedel–Crafts catalyst.

Double salts / alums: KAl(SO₄)₂·12H₂O (potash alum) crystallises as one solid but ions free in solution. General M⁺M′³⁺(SO₄)₂·12H₂O. Used as mordant and water purifier. Variants: chrome alum, ferric alum, ammonium alum.

Al₂Cl₆ dimer  |  KAl(SO₄)₂·12H₂O potash alum
Lewis-acid dimer · double salt for mordant & water treatment

Section 2: Group 14 — Carbon and Silicon (19.3–19.4)

Catenation is strong for carbon (strong C–C) but weak for silicon (weaker Si–Si) — hence vast organic chemistry vs few silanes.

Diamond vs Graphite Diamond sp³ · 3D network Hard · insulator · inert Cutting · jewellery Graphite sp² · layers Soft · conductor Electrodes · lubricant Same element · different bonding → different properties
Allotropy of carbon: structure determines hardness, conductivity and reactivity.

Diamond: each C sp³-linked to four others in 3D; hardest natural substance; unreactive; burns above ~800°C to CO₂; jewellery and abrasives.

Graphite: sp² layers (hexagons); fourth e⁻ delocalised → electrical conductor; layers slip (lubricant); electrodes, pencils, crucibles. Fullerenes (e.g. C₆₀) — soccer-ball cages.

Oxides: CO neutral, toxic (Hb binding), industrial fuel and reductant (blast furnace Fe₂O₃ + 3CO). CO₂ acidic, dry ice (sublimes −78°C), carbonated drinks, soda manufacture. SiO₂ (silica, quartz): acidic macromolecule of SiO₄ tetrahedra sharing corners; high melting; glass, sand; reacts with HF/F₂ to SiF₄; alkalies → silicates.

Halides: CCl₄ and SiCl₄ both tetrahedral (sp³). CCl₄ not hydrolysed; SiCl₄ + 4H₂O → Si(OH)₄ + 4HCl because Si has empty 3d orbitals for H₂O attack. Si forms SiF₆²⁻; carbon cannot form CF₆²⁻.

SiC (carborundum): SiO₂ + 3C → SiC + 2CO; diamond-like Si–C network; abrasive.

Silicones: polymers with –Si–O–Si– backbone and organic R groups; from RCl + Si (Cu, 300°C) then hydrolysis/condensation; water-repellent, flexible, thermally stable.

Silicates & zeolites: based on SiO₄ tetrahedra sharing oxygen (isolated units, Si₂O₇, chains with two O shared, sheets, 3D frameworks). Zeolites: open frameworks used as molecular sieves, ion exchangers and catalysts — water softener and petrochemical cracking applications.

Why few silanes but millions of hydrocarbons? C–C bond energy is high and C forms strong multiple bonds; Si–Si is weaker and Si prefers bonding to O (Si–O very strong). Life’s backbone is carbon; Earth’s crust backbone is silica and silicates.

CCl₄ no hydrolysis  |  SiCl₄ + 4H₂O → Si(OH)₄ + 4HCl
Empty 3d on Si allows nucleophilic attack by water · C has no d-orbitals

Section 3: Group 15 — Nitrogen and Phosphorus (19.5–19.6)

N, P, As, Sb, Bi. Mostly covalent compounds; N forms N³⁻ with reactive metals; Sb³⁺, Bi³⁺ via inert pair. N≡N triple bond makes N₂ inert at room temperature. N and P are essential in proteins, DNA and bones (phosphate).

Dinitrogen: 78% of air; laboratory from NH₄NO₂ heat or azides; industry by fractional distillation of liquid air. Forms nitrides with Li, Mg, Al; Haber NH₃; lightning gives NO (start of natural nitrogen fixation to nitrates).

Haber Process — Ammonia N₂ + 3H₂1 : 3 Fe catalyst~200 atm · 400–500°C 2NH₃ Exothermic · cool & liquefy NH₃ · recycle unreacted N₂/H₂ Fertilizer · HNO₃ (Ostwald) · Solvay · refrigerant
Haber synthesis: high pressure favours product; moderate temperature balances rate and yield.
N₂ + 3H₂ ⇌ 2NH₃  |  ΔH = −46 kJ mol⁻¹
Haber: Fe catalyst · high P · 673–773 K · NH₃ pyramidal, HNH ~107°

Ammonia: lab from NH₄⁺ salt + base or Mg₃N₂ + H₂O. Colourless, pungent, highly soluble; weak base (NH₃ + H₂O ⇌ NH₄⁺ + OH⁻). Burns in O₂; catalytic oxidation to NO (Ostwald start); reduces CuO/PbO; forms ammonium salts; excess Cl₂ → N₂, excess Cl₂ conditions can give NCl₃; aqueous NH₃ precipitates metal hydroxides and forms ammine complexes [Cu(NH₃)₄]²⁺, [Ag(NH₃)₂]⁺.

Nitric acid (Ostwald): 4NH₃ + 5O₂ → 4NO + 6H₂O (Pt, hot) → 2NO + O₂ → 2NO₂ → 3NO₂ + H₂O → 2HNO₃ + NO. Lab: NaNO₃ + H₂SO₄. Strong acid and oxidant (C, S, P, I₂, Cu, Zn — products depend on concentration). Conc. HNO₃ passivates Al (oxide film). Uses: fertilizers, explosives, aqua regia, oxidant, rocket propellant (fuming).

4NH₃ + 5O₂ → 4NO → NO₂ → HNO₃ (Ostwald)
Catalytic oxidation of ammonia is the industrial route to nitric acid

Phosphorus allotropes: White — P₄ tetrahedra, 60° angles, strained, waxy, toxic, reactive; red — polymeric, from heating white, denser, safer; black — high pressure, layered, conducting, graphite-like.

PCl₃: P₄ + 6Cl₂ → 4PCl₃; hydrolyses to H₃PO₃ + HCl (d-orbitals allow expansion). PCl₅ also known for heavier congeners’ ability to form 5-covalent compounds (N cannot).

Fertilizers: nitrogenous (NH₃, urea, ammonium salts), phosphatic (superphosphate, etc.), mixed NPK — essential for agriculture after natural soil N is depleted. Industrial N₂ fixation (Haber) and natural fixation (lightning, legumes/bacteria) both feed the nitrogen cycle.

Phosphorus Allotropes White P₄Strained · reactive RedPolymeric · safer BlackLayered · conductor White → red on heating · black under high pressure
Three main allotropes of phosphorus — structure controls reactivity and safety.

Exam Connections and Chapter Summary

High-yield topics: boric acid as Lewis acid; diborane 3c–2e structure; BF₃/AlCl₃ as Lewis acids and catalysts; potash alum formula and uses; diamond vs graphite (hybridisation, properties, uses); CO toxicity; CCl₄ vs SiCl₄ hydrolysis; SiC; silicones; Haber conditions and equilibrium logic; Ostwald steps; white vs red P; fertilizer types.

Connect to L18 (inert pair, first-element anomalies, empty d-orbitals) and L13 (industrial catalysis). L20 continues with Groups 16–18 (O, S, halogens, noble gases).

Master structure sketches (B₂H₆, Al₂Cl₆, diamond/graphite, NH₃ pyramid) and process flow charts (Haber, Ostwald) — most NIOS marks on this chapter reward clear diagrams and balanced equations more than long prose.

Intext-style checks: formula of borax and boric acid; one preparation of B₂H₆; alum general formula; Al₂Cl₆ structure; diamond properties not shared by graphite; hybridisation in diamond/graphite; CCl₄ vs SiCl₄; CO vs CO₂ acidity; Haber and Ostwald outlines; white P structure; fertilizer classes. If you can answer these with equations, you are exam-ready for L19.

MCQ Quiz — L19 p-Block Elements and Their Compounds-I

0 / 10 correct

Flashcards — L19

1 / 18

Golden Rules — L19 p-Block Elements and Their Compounds-I

Most exam-important points from this chapter:

Group 13

H₃BO₃ Lewis acid; B₂H₆ has 3c–2e bridges; BF₃/Al₂Cl₆ Lewis acids & catalysts; alum = double salt KAl(SO₄)₂·12H₂O.

Carbon allotropes

Diamond sp³ hard insulator; graphite sp² soft conductor; C₆₀ fullerene. Structure → properties.

C vs Si

Catenation strong for C. CCl₄ no hydrolysis; SiCl₄ yes (3d). SiC abrasive; silicones & silicates/zeolites.

Nitrogen industry

Haber NH₃ (high P, Fe). Ostwald HNO₃ via NO. NH₃ weak base; HNO₃ strong acid/oxidant.

Phosphorus & fertilizers

White P₄ reactive; red polymeric; black layered. N/P/K fertilizers from NH₃ and phosphates.

H₃BO₃ Lewis acid
B₂H₆: 3c–2e bridges
BF₃ / Al₂Cl₆ Lewis acids
KAl(SO₄)₂·12H₂O alum
Diamond sp³ · Graphite sp²
CCl₄ no hydrolysis · SiCl₄ yes
Haber: N₂+3H₂⇌2NH₃
Ostwald → HNO₃
P₄ white · red · black

Section 1: Group 13 — Boron & Aluminium

NIOS Chemistry 313, Module 6 — p-Block Elements and Their Compounds–I (Groups 13–15, sections 19.1–19.6).

Boric Acid & Borax

Na₂B₄O₇ + H₂SO₄ + 5H₂O → Na₂SO₄ + 4H₃BO₃

Lewis acid: B(OH)₃ + 2H₂O → [B(OH)₄]⁻ + H₃O⁺ · 2D sheets via H-bonds

Borax: Na₂B₄O₇·10H₂O · flux, glass, buffer, glazes

Diborane B₂H₆ — Bridge Bonding

4BCl₃ + 3LiAlH₄ → 2B₂H₆ + … · 8BF₃ + 6LiH → B₂H₆ + 6LiBF₄

4 terminal B–H (2c–2e) + 2 bridges B–H–B (3c–2e) · 12 valence e⁻ for 8 B–H contacts

Burns: B₂H₆ + 3O₂ → B₂O₃ + 3H₂O (ΔH = −1976 kJ) · Hydrolyses to H₃BO₃ + H₂

BF₃ & Al₂Cl₆

B₂O₃ + 6HF → 2BF₃ + 3H₂O · Lewis acid · F₃B←NH₃ · Friedel–Crafts catalyst

Al₂Cl₆ dimer: Cl bridges complete Al octets · Anhydrous AlCl₃ catalyst · +H₂O → [Al(H₂O)₆]³⁺

Potash alum: KAl(SO₄)₂·12H₂O · mordant · water purification

Section 2: Group 14 — Carbon & Silicon

Allotropes & Oxides

Diamond: sp³ 3D network · hardest · inert · jewellery, cutting

Graphite: sp² layers · free e⁻ · conductor · lubricant, electrodes, pencils

Fullerene C₆₀: soccer-ball cage

CO toxic (Hb complex) · CO₂ acidic, dry ice · SiO₂ macromolecule (quartz)

Halides, SiC, Silicones

CCl₄ not hydrolysed (no d-orbitals) · SiCl₄ + 4H₂O → Si(OH)₄ + 4HCl

SiO₂ + 3C → SiC + 2CO (carborundum — abrasive) · diamond-like lattice

Silicones: –Si–O–Si– backbone with R groups · water-repellent polymers

Silicates / zeolites: SiO₄ tetrahedra share O · molecular sieves, catalysts

Section 3: Group 15 — N & P

Haber Process — Ammonia

N₂ + 3H₂ ⇌ 2NH₃ · ΔH = −46 kJ mol⁻¹ · ~200 atm · 673–773 K · Fe catalyst

NH₃ pyramidal · HNH ~107° · weak base · fertilizer, HNO₃, Solvay, refrigerant

Ostwald Process — Nitric Acid

4NH₃ + 5O₂ → 4NO + 6H₂O (Pt, 1173 K) · 2NO + O₂ → 2NO₂ · 3NO₂ + H₂O → 2HNO₃ + NO

Strong acid · oxidant · aqua regia · fertilizers & explosives (TNT, nitroglycerine)

Al becomes passive in conc. HNO₃ (oxide film)

Phosphorus Allotropes & PCl₃

White: P₄ tetrahedra · strained · reactive · toxic

Red: polymeric · from heating white · safer

Black: layered · conductor · high pressure

P₄ + 6Cl₂ → 4PCl₃ · PCl₃ + 3H₂O → H₃PO₃ + 3HCl

Section 2: Definitions

3c–2e bond: Three-centre two-electron bond in diborane bridges (B–H–B).

Lewis acid: Electron-pair acceptor — BF₃, AlCl₃, B(OH)₃.

Catenation: Self-linking of atoms in chains/rings — strong for C, weak for Si.

Double salt (alum): Crystallises as one solid; ions free in solution — KAl(SO₄)₂·12H₂O.

Haber process: Industrial NH₃ from N₂ + H₂ under pressure with Fe catalyst.

Section 3: Visual Map

L19 Map — Groups 13–15 Compounds B: H₃BO₃, B₂H₆, BF₃ Al: Al₂Cl₆, alum C/Si: diamond, SiCl₄ N: Haber NH₃ · Ostwald HNO₃ · P: white/red/black · fertilizers Key: 3c–2e · Lewis acids · CCl₄ vs SiCl₄ · catenation · passivity of Al

Section 5: Q&A (12 Questions)

Q1: Why is boric acid a Lewis acid?

B accepts OH⁻ from water to form [B(OH)₄]⁻ and release H₃O⁺ — not a simple proton donor.

Q2: Bonding in diborane?

Four normal 2c–2e B–H terminal bonds + two 3c–2e B–H–B bridges (electron-deficient).

Q3: Why does AlCl₃ dimerise?

Al has only 6 e⁻ after three bonds; Cl bridges donate pairs to complete octets → Al₂Cl₆.

Q4: Diamond vs graphite hybridisation?

Diamond sp³ 3D; graphite sp² layers with delocalised π electrons.

Q5: Why CCl₄ not hydrolysed but SiCl₄ is?

Si has empty 3d orbitals accepting H₂O lone pair; C has no d-orbitals.

Q6: Carborundum formula and use?

SiC — abrasive; diamond-like Si–C tetrahedral network.

Q7: Haber process conditions?

N₂:H₂ = 1:3 · high pressure (~200 atm) · 400–500°C · Fe catalyst · recycle unreacted gas.

Q8: Ostwald process outline?

NH₃ → NO (Pt) → NO₂ → HNO₃ with water.

Q9: Why is white P reactive?

P₄ tetrahedra with 60° angles — highly strained; weak van der Waals packing.

Q10: Alum general formula?

M⁺M′³⁺(SO₄)₂·12H₂O e.g. KAl(SO₄)₂·12H₂O.

Q11: CO toxicity?

Binds haemoglobin more strongly than O₂ → oxygen transport fails.

Q12: Why Al passive in conc. HNO₃?

Protective Al₂O₃ film forms and stops further reaction.

Section 6: Tips & Exam Hacks

Memory Aids

  • B₂H₆: "Banana bonds" (3c–2e bridges)
  • Diamond/graphite: "sp³ hard / sp² soft layers"
  • CCl₄ vs SiCl₄: "No d / has d"
  • Haber: "High P, moderate T, Fe"
  • Ostwald: "Ammonia to acid via NO"

Exam Tips

  • Draw B₂H₆ with bridges above/below plane
  • Al₂Cl₆ dimer structure for Friedel–Crafts
  • Catenation: C–C > Si–Si
  • White P toxic & reactive; red safer
  • Fertilizers: N (NH₃, urea), P (phosphates), mixed NPK

Section 8: Quick Reference

• H₃BO₃ Lewis · Borax · B₂H₆ 3c–2e · BF₃ / Al₂Cl₆ catalysts · Alum mordant

• Diamond sp³ · Graphite sp² · C₆₀ · CO toxic · CO₂ dry ice · SiO₂ network

• CCl₄ inert to H₂O · SiCl₄ hydrolyses · SiC abrasive · silicones · zeolites

• Haber NH₃ · Ostwald HNO₃ · P₄ white/red/black · fertilizers

Remember: ✓ Electron-deficient B/Al ✓ Catenation of C ✓ d-orbitals of Si ✓ N≡N inertness ✓ P₄ strain

PYQ — Previous Year Questions

Extracted from NIOS Chemistry (313) board exam papers in your PDF. Chapter L19 — p-Block Elements and Their Compounds-I only. Use Model Answer for marking points; Explanation for concept clarity.

L19 — p-Block Elements and Their Compounds-I

9 question(s) · Sources: 313/MAY/205A, 313/MAY/205B, 313/MAY/205C

Section A — MCQ / Objective (from papers)

PYQ1. The number of oxygen atoms furnished by two molecules of permanganate in acidic medium is — (A) Aåbr¶ ‘mܶ‘ ‘

1 mark · Q9 · 313/MAY/205A

Model Answer

Answer using key concepts from L19 (definitions, equations, and one example where useful). Stay within the suggested word range for a 1-mark NIOS question.

Explanation

Cross-check with L19 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.

How to write for NIOS: Use 1 mark — concise correct choice/fact. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205A · Q9 · 1 mark(s) · L19.

PYQ2. Complete the following choosing from the given options : ( 96 g, 3 g, 48 g, 34 g, 30 g, 28 g ) 4Fe(s) + 3O2(g)2Fe2O3(s) In this reaction, the mass of oxygen reacting is _____. N2(g) + 3H2(g)2NH3(g) The grams of NH3 produced in the above reaction are _____

2 marks · Q17 · 313/MAY/205A

Model Answer

Answer using key concepts from L19 (definitions, equations, and one example where useful). Stay within the suggested word range for a 2-mark NIOS question.

Explanation

Cross-check with L19 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.

How to write for NIOS: Use 30–50 words (VSA) or short objective. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205A · Q17 · 2 mark(s) · L19.

PYQ3. Read the passage given below and answer the following questions : The binary compounds of oxygen with other elements (metals or non-metals) are called oxides. An understanding of the nature of an oxide provides a clue to the nature of the element which forms the oxide. These oxides may be acidic, basic, amphoteric or neutral depending on the element with which they are formed. Silicon dioxide is which type of oxide? Name two elements which form neutral oxides.

2 marks · Q22 · 313/MAY/205A

Model Answer

Answer using key concepts from L19 (definitions, equations, and one example where useful). Stay within the suggested word range for a 2-mark NIOS question.

Explanation

Cross-check with L19 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.

How to write for NIOS: Use 30–50 words (VSA) or short objective. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205A · Q22 · 2 mark(s) · L19.

PYQ4. The number of oxygen atoms furnished by two molecules of permanganate in acidic medium is — (A) Aåbr¶ ‘mܶ‘ ‘

1 mark · Q3 · 313/MAY/205B

Model Answer

Answer using key concepts from L19 (definitions, equations, and one example where useful). Stay within the suggested word range for a 1-mark NIOS question.

Explanation

Cross-check with L19 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.

How to write for NIOS: Use 1 mark — concise correct choice/fact. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205B · Q3 · 1 mark(s) · L19.

PYQ5. Read the passage given below and answer the following questions : The binary compounds of oxygen with other elements (metals or non-metals) are called oxides. An understanding of the nature of an oxide provides a clue to the nature of the element which forms the oxide. These oxides may be acidic, basic, amphoteric or neutral depending on the element with which they are formed. Silicon dioxide is which type of oxide? Name two elements which form neutral oxides.

2 marks · Q25 · 313/MAY/205B

Model Answer

Answer using key concepts from L19 (definitions, equations, and one example where useful). Stay within the suggested word range for a 2-mark NIOS question.

Explanation

Cross-check with L19 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.

How to write for NIOS: Use 30–50 words (VSA) or short objective. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205B · Q25 · 2 mark(s) · L19.

PYQ6. The number of oxygen atoms furnished by two molecules of permanganate in acidic medium is — (A) Aåbr¶ ‘mܶ‘ ‘

1 mark · Q13 · 313/MAY/205C

Model Answer

Answer using key concepts from L19 (definitions, equations, and one example where useful). Stay within the suggested word range for a 1-mark NIOS question.

Explanation

Cross-check with L19 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.

How to write for NIOS: Use 1 mark — concise correct choice/fact. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205C · Q13 · 1 mark(s) · L19.

PYQ7. Complete the following choosing from the given options : ( 34, 28, 17, H3O+, H2O, H2O4 ) 2NH (g) In the above reaction, _____ g of NH3 is produced. The empirical formula of H2O is _____

2 marks · Q17 · 313/MAY/205C

Model Answer

Answer using key concepts from L19 (definitions, equations, and one example where useful). Stay within the suggested word range for a 2-mark NIOS question.

Explanation

Cross-check with L19 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.

How to write for NIOS: Use 30–50 words (VSA) or short objective. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205C · Q17 · 2 mark(s) · L19.

PYQ8. Read the passage given below and answer the following questions : The binary compounds of oxygen with other elements (metals or non-metals) are called oxides. An understanding of the nature of an oxide provides a clue to the nature of the element which forms the oxide. These oxides may be acidic, basic, amphoteric or neutral depending on the element with which they are formed. Silicon dioxide is which type of oxide? Name two elements which form neutral oxides.

2 marks · Q19 · 313/MAY/205C

Model Answer

Answer using key concepts from L19 (definitions, equations, and one example where useful). Stay within the suggested word range for a 2-mark NIOS question.

Explanation

Cross-check with L19 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.

How to write for NIOS: Use 30–50 words (VSA) or short objective. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205C · Q19 · 2 mark(s) · L19.

PYQ9. Match the items in Column—I with Column—II : Column—I Column—II Groups with –I effect —CH3, —H, (CH3)3C— Groups with +I effect Presence of aluminium chloride/AlCl3 Dehydrating agent (iii) — NO , — CN, — OH Molecular rearrangements conc. sulphuric acid/H2SO4

2 marks · Q24 · 313/MAY/205C

Model Answer

Answer using key concepts from L19 (definitions, equations, and one example where useful). Stay within the suggested word range for a 2-mark NIOS question.

Explanation

Cross-check with L19 notes. Structure: definition/law → working → conclusion. Partial marks for correct equations even if explanation is short.

How to write for NIOS: Use 30–50 words (VSA) or short objective. Open with definition/equation, then reason, end with conclusion. Paper 313/MAY/205C · Q24 · 2 mark(s) · L19.

Problem Solving — L19 p-Block Elements and Their Compounds-I

Six problems spanning this chapter’s NIOS syllabus. Every question is built from the notes and formula sheet: solve with equations first, then read the formal textbook-style write-up, the easy explanation, and the topic in depth (formulas, meaning, exam tips). If the question says draw, a labelled pencil sketch is provided. Explanations open by default.

Question 1 of 6N2

Why is N₂ chemically inert at room temperature?

Solution — step by step with formulas

  1. Very strong N≡N triple bond (high bond enthalpy).

Final answer: Strong triple bond

Textbook formal language

High bond dissociation enthalpy of N₂.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

Hard to break N≡N, so air N₂ is unreactive.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — Dinitrogen

Fixed industrially by Haber process.

Linked to chapter notes (L19). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.
Question 2 of 6NH3

State shape and approximate bond angle of NH₃.

Solution — step by step with formulas

  1. Pyramidal; about 107°.

Final answer: Pyramidal ~107°

Textbook formal language

VSEPR: three bond pairs + one lone pair on nitrogen.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

Lone pair pushes hydrogens down into a pyramid.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — Ammonia

Basic due to lone pair.

Linked to chapter notes (L19). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.
Question 3 of 6HNO3

Outline Ostwald process for manufacture of HNO₃.

Solution — step by step with formulas

  1. Catalytic oxidation of NH₃ → NO → NO₂ → absorption in water to HNO₃.

Final answer: NH₃ → NO → NO₂ → HNO₃

Textbook formal language

Industrial Ostwald route.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

Burn ammonia, make NO₂, dissolve.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — Nitric acid

Pt catalyst.

Linked to chapter notes (L19). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.
Question 4 of 6P

Name two allotropes of phosphorus.

Solution — step by step with formulas

  1. White and red phosphorus.

Final answer: White and red

Textbook formal language

White P is molecular P₄; red is polymeric.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

White is more reactive/toxic.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — Phosphorus allotropes

Store white under water.

Linked to chapter notes (L19). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.
Question 5 of 6O2

Why is O₂ paramagnetic?

Solution — step by step with formulas

  1. Two unpaired electrons in molecular orbital configuration.

Final answer: Unpaired e⁻ in MO diagram

Textbook formal language

MO theory places two electrons unpaired in π* orbitals.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

Liquid oxygen is attracted to a magnet.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — Oxygen

Classic evidence for MO theory.

Linked to chapter notes (L19). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.
Question 6 of 6O3

Give one use of ozone.

Solution — step by step with formulas

  1. Water purification / disinfectant / bleaching (strong oxidant).

Final answer: Disinfection / oxidant

Textbook formal language

O₃ is a strong oxidising allotrope of oxygen.

Working formulas: (see solution steps). State the definition or law first (NIOS style), use SI units, and box the final numerical answer with unit.

Easy language (same idea, plain words)

Kills microbes by oxidation.

Read once for the idea, once for the numbers. Write the formula, substitute, then simplify. Check whether you used moles, grams, or litres correctly.

Topic in depth — Ozone

Stratospheric ozone absorbs UV.

Linked to chapter notes (L19). Remember: (see solution steps). Most exam errors are unit mix-ups (g vs mol, mL vs L) or wrong mole ratios from the equation.

Exam tip

Write (see solution steps) before substituting. Keep three significant figures until the end when data allow.

Common mistakes

  • Confusing mass (g) with amount of substance (mol).
  • Forgetting Avogadro’s number unit mol⁻¹ or STP volume 22.7 L mol⁻¹ (1 bar).
  • Using wrong mole ratio from the balanced equation.
  • Mixing up empirical and molecular formulas.